# collatz2.py

def coll(n):
    z = 0
    m = n
    while m != 1:
        z += 1
        if m%2==0: 
                m = m/2
        else:
                m = 3*m+1
    return z
       
for n in range(1,100,1):
    print("Bei n = ", int(n), "braucht es ",coll(n)," Schritte")